Optimal. Leaf size=112 \[ -\frac{b^2 (A b-2 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x}}{\sqrt{a}}\right )}{8 a^{5/2}}+\frac{b \sqrt{a+b x} (A b-2 a B)}{8 a^2 x}+\frac{\sqrt{a+b x} (A b-2 a B)}{4 a x^2}-\frac{A (a+b x)^{3/2}}{3 a x^3} \]
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Rubi [A] time = 0.0499156, antiderivative size = 112, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.278, Rules used = {78, 47, 51, 63, 208} \[ -\frac{b^2 (A b-2 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x}}{\sqrt{a}}\right )}{8 a^{5/2}}+\frac{b \sqrt{a+b x} (A b-2 a B)}{8 a^2 x}+\frac{\sqrt{a+b x} (A b-2 a B)}{4 a x^2}-\frac{A (a+b x)^{3/2}}{3 a x^3} \]
Antiderivative was successfully verified.
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Rule 78
Rule 47
Rule 51
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\sqrt{a+b x} (A+B x)}{x^4} \, dx &=-\frac{A (a+b x)^{3/2}}{3 a x^3}+\frac{\left (-\frac{3 A b}{2}+3 a B\right ) \int \frac{\sqrt{a+b x}}{x^3} \, dx}{3 a}\\ &=\frac{(A b-2 a B) \sqrt{a+b x}}{4 a x^2}-\frac{A (a+b x)^{3/2}}{3 a x^3}-\frac{(b (A b-2 a B)) \int \frac{1}{x^2 \sqrt{a+b x}} \, dx}{8 a}\\ &=\frac{(A b-2 a B) \sqrt{a+b x}}{4 a x^2}+\frac{b (A b-2 a B) \sqrt{a+b x}}{8 a^2 x}-\frac{A (a+b x)^{3/2}}{3 a x^3}+\frac{\left (b^2 (A b-2 a B)\right ) \int \frac{1}{x \sqrt{a+b x}} \, dx}{16 a^2}\\ &=\frac{(A b-2 a B) \sqrt{a+b x}}{4 a x^2}+\frac{b (A b-2 a B) \sqrt{a+b x}}{8 a^2 x}-\frac{A (a+b x)^{3/2}}{3 a x^3}+\frac{(b (A b-2 a B)) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b x}\right )}{8 a^2}\\ &=\frac{(A b-2 a B) \sqrt{a+b x}}{4 a x^2}+\frac{b (A b-2 a B) \sqrt{a+b x}}{8 a^2 x}-\frac{A (a+b x)^{3/2}}{3 a x^3}-\frac{b^2 (A b-2 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x}}{\sqrt{a}}\right )}{8 a^{5/2}}\\ \end{align*}
Mathematica [C] time = 0.0177053, size = 57, normalized size = 0.51 \[ -\frac{(a+b x)^{3/2} \left (a^3 A+b^2 x^3 (2 a B-A b) \, _2F_1\left (\frac{3}{2},3;\frac{5}{2};\frac{b x}{a}+1\right )\right )}{3 a^4 x^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 91, normalized size = 0.8 \begin{align*} 2\,{b}^{2} \left ({\frac{1}{{b}^{3}{x}^{3}} \left ( 1/16\,{\frac{ \left ( Ab-2\,Ba \right ) \left ( bx+a \right ) ^{5/2}}{{a}^{2}}}-1/6\,{\frac{Ab \left ( bx+a \right ) ^{3/2}}{a}}+ \left ( -1/16\,Ab+1/8\,Ba \right ) \sqrt{bx+a} \right ) }-1/16\,{\frac{Ab-2\,Ba}{{a}^{5/2}}{\it Artanh} \left ({\frac{\sqrt{bx+a}}{\sqrt{a}}} \right ) } \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.23407, size = 479, normalized size = 4.28 \begin{align*} \left [-\frac{3 \,{\left (2 \, B a b^{2} - A b^{3}\right )} \sqrt{a} x^{3} \log \left (\frac{b x - 2 \, \sqrt{b x + a} \sqrt{a} + 2 \, a}{x}\right ) + 2 \,{\left (8 \, A a^{3} + 3 \,{\left (2 \, B a^{2} b - A a b^{2}\right )} x^{2} + 2 \,{\left (6 \, B a^{3} + A a^{2} b\right )} x\right )} \sqrt{b x + a}}{48 \, a^{3} x^{3}}, -\frac{3 \,{\left (2 \, B a b^{2} - A b^{3}\right )} \sqrt{-a} x^{3} \arctan \left (\frac{\sqrt{b x + a} \sqrt{-a}}{a}\right ) +{\left (8 \, A a^{3} + 3 \,{\left (2 \, B a^{2} b - A a b^{2}\right )} x^{2} + 2 \,{\left (6 \, B a^{3} + A a^{2} b\right )} x\right )} \sqrt{b x + a}}{24 \, a^{3} x^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 28.223, size = 666, normalized size = 5.95 \begin{align*} - \frac{66 A a^{3} b^{3} \sqrt{a + b x}}{96 a^{6} + 144 a^{5} b x - 144 a^{4} \left (a + b x\right )^{2} + 48 a^{3} \left (a + b x\right )^{3}} + \frac{80 A a^{2} b^{3} \left (a + b x\right )^{\frac{3}{2}}}{96 a^{6} + 144 a^{5} b x - 144 a^{4} \left (a + b x\right )^{2} + 48 a^{3} \left (a + b x\right )^{3}} - \frac{30 A a b^{3} \left (a + b x\right )^{\frac{5}{2}}}{96 a^{6} + 144 a^{5} b x - 144 a^{4} \left (a + b x\right )^{2} + 48 a^{3} \left (a + b x\right )^{3}} - \frac{10 A a b^{3} \sqrt{a + b x}}{- 8 a^{4} - 16 a^{3} b x + 8 a^{2} \left (a + b x\right )^{2}} - \frac{5 A a b^{3} \sqrt{\frac{1}{a^{7}}} \log{\left (- a^{4} \sqrt{\frac{1}{a^{7}}} + \sqrt{a + b x} \right )}}{16} + \frac{5 A a b^{3} \sqrt{\frac{1}{a^{7}}} \log{\left (a^{4} \sqrt{\frac{1}{a^{7}}} + \sqrt{a + b x} \right )}}{16} + \frac{6 A b^{3} \left (a + b x\right )^{\frac{3}{2}}}{- 8 a^{4} - 16 a^{3} b x + 8 a^{2} \left (a + b x\right )^{2}} + \frac{3 A b^{3} \sqrt{\frac{1}{a^{5}}} \log{\left (- a^{3} \sqrt{\frac{1}{a^{5}}} + \sqrt{a + b x} \right )}}{8} - \frac{3 A b^{3} \sqrt{\frac{1}{a^{5}}} \log{\left (a^{3} \sqrt{\frac{1}{a^{5}}} + \sqrt{a + b x} \right )}}{8} - \frac{10 B a^{2} b^{2} \sqrt{a + b x}}{- 8 a^{4} - 16 a^{3} b x + 8 a^{2} \left (a + b x\right )^{2}} + \frac{6 B a b^{2} \left (a + b x\right )^{\frac{3}{2}}}{- 8 a^{4} - 16 a^{3} b x + 8 a^{2} \left (a + b x\right )^{2}} + \frac{3 B a b^{2} \sqrt{\frac{1}{a^{5}}} \log{\left (- a^{3} \sqrt{\frac{1}{a^{5}}} + \sqrt{a + b x} \right )}}{8} - \frac{3 B a b^{2} \sqrt{\frac{1}{a^{5}}} \log{\left (a^{3} \sqrt{\frac{1}{a^{5}}} + \sqrt{a + b x} \right )}}{8} - \frac{B b^{2} \sqrt{\frac{1}{a^{3}}} \log{\left (- a^{2} \sqrt{\frac{1}{a^{3}}} + \sqrt{a + b x} \right )}}{2} + \frac{B b^{2} \sqrt{\frac{1}{a^{3}}} \log{\left (a^{2} \sqrt{\frac{1}{a^{3}}} + \sqrt{a + b x} \right )}}{2} - \frac{B b \sqrt{a + b x}}{a x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24911, size = 173, normalized size = 1.54 \begin{align*} -\frac{\frac{3 \,{\left (2 \, B a b^{3} - A b^{4}\right )} \arctan \left (\frac{\sqrt{b x + a}}{\sqrt{-a}}\right )}{\sqrt{-a} a^{2}} + \frac{6 \,{\left (b x + a\right )}^{\frac{5}{2}} B a b^{3} - 6 \, \sqrt{b x + a} B a^{3} b^{3} - 3 \,{\left (b x + a\right )}^{\frac{5}{2}} A b^{4} + 8 \,{\left (b x + a\right )}^{\frac{3}{2}} A a b^{4} + 3 \, \sqrt{b x + a} A a^{2} b^{4}}{a^{2} b^{3} x^{3}}}{24 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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